Leetcode - Power of Three Solution
Given an integer n, return true if it is a power of three. Otherwise, return false.
An integer n is a power of three, if there exists an integer x such that n == 3x.
Example 1:
Input: n = 27
Output: trueExample 2:
Input: n = 0
Output: falseExample 3:
Input: n = 9
Output: trueExample 4:
Input: n = 45
Output: falseConstraints:
-231 <= n <= 231 - 1
Follow up: Could you solve it without loops/recursion?
Solution in python
class Solution:
def isPowerOfThree(self, n: int) -> bool:
if n <= 0:
return False
return (math.log10(n) / math.log10(3))%1 == 0